3=x^2-8x+1

Solution for 3=x^2-8x+1 equation:

3=x^2-8x+1

We move all terms to the left:

3-(x^2-8x+1)=0

We get rid of parentheses

-x^2+8x-1+3=0

We add all the numbers together, and all the variables

-1x^2+8x+2=0

a = -1; b = 8; c = +2;
Δ = b2-4ac
Δ = 82-4·(-1)·2
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-6\sqrt{2}}{2*-1}=\frac{-8-6\sqrt{2}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+6\sqrt{2}}{2*-1}=\frac{-8+6\sqrt{2}}{-2}
$